Question

How many moles of ethyl alcohol, C2H5OH, are present in 65 mL of a 1.5 M solution?

Answer 1

Answer:

0.0975 moles

Explanation:

molarity means no. of moles in 1 litre solution

so 1000ml solution have moles= 1.5

1ml solution have moles= 1.5/1000

then 65ml solution have moles= (1.5÷1000)×65

=0.0975 moles of ethyl alcohol

Answer 2

we have to find the no of moles of ethyl alcohol present in 65 ml of a 1.5M solution.

solution : molarity of the solution = 1.5 M, which means 1.5 moles of ethyl alcohol present in 1 L of solution.

∵ in 1L = 1000 ml solution of ethyl alcohol , 1.5 moles of ethyl alcohol.

∴ in 1 ml of solution of ethyl alcohol, 1.5/1000 mole of ethyl alcohol.

∴ in 65 ml of ethyl alcohol solution, 1.5/1000 × 65 = 0.0975 mol of ethyl alcohol.

therefore the number of moles of ethyl alcohol is 0.0975.

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