Question

how many moles of fe are present in 80g of rust?
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Answer 1

Explanation:

We get that the number of moles of FeO in 30g is equal to 30/72 = 5/12 moles. Therefore there are also 5/12 moles of Fe present in 30g of FeO. Assuming you had 30g of the latter. The Mr value of Fe2O3 is equal to 2(56) + 3(16) = 160.