How many moles of Fe in 30g of rust
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Since for every mole of Fe2O3 there are 2 moles of Fe present, there are 3/16 * 2 = 3/8 moles of Fe present in 30g of Fe2O3.
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The formula of rust is (Fe2O3)
Since for every mole of Fe2O3 there are 2 moles of Fe present, there are 3/16 * 2 = 3/8 moles of Fe present in 30g of Fe2O3.
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