How many moles of ferric alum (NH4
)2
SO4
·
Fe2
(SO4
)
3
·24H2
O can be made from the sample
of Fe containing 0.0056 g of it ?
[Atomic mass of Fe = 56 u]
(1) 10–4 mol (2) 0.5 × 10–4 mol
(3) 0.33 × 10–4 mol (4) 2 × 10–4 mol
lucky3813:
hiii
Answers
Answered by
13
112g of Fe is contained in---->1 mole of ferric alum
therefore 5.6 * 10^-3g of Fe will be in ----->(1/112)*5.6*10^-3
=====> 0.5 * 10^-4 mol.of ferric alum.
The ans. is (2) 0.5 * 10^-4
Hope it helps.
therefore 5.6 * 10^-3g of Fe will be in ----->(1/112)*5.6*10^-3
=====> 0.5 * 10^-4 mol.of ferric alum.
The ans. is (2) 0.5 * 10^-4
Hope it helps.
Similar questions