How many moles of gas are needed to fill a 2000 ml container at 77 ° F and a pressure of 1.0104 Bar.
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Answer:-
Given:
Volume of gas (V) = 2000 ml = 2 L
Pressure (P) = 1.0104 bar.
Temperature (T) =( 77° + 459.67)*5/9 = 298.15° K
Gas Constant (R) = 8.31 L*bar/K*mol.
Let ,
number of moles = n.
By using Ideal Gas Equation,
→ PV = nRT
→ (1.0104)(2) = n(8.31)(298.15)
→ n = 2.0208/2477.6
→ n = 0.0008 mol.
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