Question

How many moles of glucose are in 19.1g of glucose?

Answer 1

There are 0.10601929839869847 moles of glucose are in 19.1g of glucose

Answer 2

0.106 moles of glucose are there in 19.1 g of glucose

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{19.1g}{18g/mol}=0.106moles$

Thus there are 0.106 moles of glucose.

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