how many moles of H2O are formed on combustion of 23g of ethane?
Answers
Answer:
CH4+O2⟶CO2+2H2O
Gram molecular mass of CO2 = 12 +2(16) = 44g/mol
From the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.
Therefore moles of CH4 required to produce 22g of CO2 are:
=441×22=0.5 mol
Answer:
CH
CH 4
CH 4
CH 4 +O
CH 4 +O 2
CH 4 +O 2
CH 4 +O 2 ⟶CO
CH 4 +O 2 ⟶CO 2
CH 4 +O 2 ⟶CO 2
CH 4 +O 2 ⟶CO 2 +2H
CH 4 +O 2 ⟶CO 2 +2H 2
CH 4 +O 2 ⟶CO 2 +2H 2
CH 4 +O 2 ⟶CO 2 +2H 2 O
CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/mol
CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.
CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH
CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4
CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4
CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO
CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2
CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2
CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are:
CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: =
CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: = 44
CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: = 441
CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: = 441
CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: = 441 ×22=0.5 mol
CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: = 441 ×22=0.5 mol