Chemistry, asked by lallideepmehak, 27 days ago

how many moles of H2O are formed on combustion of 23g of ethane?​

Answers

Answered by swaranikan
2

Answer:

CH4+O2⟶CO2+2H2O

Gram molecular mass of CO2 = 12 +2(16) = 44g/mol

From the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.

Therefore moles of CH4 required to produce 22g of CO2 are:

             =441×22=0.5 mol

Answered by suhanasammakhan
0

Answer:

CH

CH 4

CH 4

CH 4 +O

CH 4 +O 2

CH 4 +O 2

CH 4 +O 2 ⟶CO

CH 4 +O 2 ⟶CO 2

CH 4 +O 2 ⟶CO 2

CH 4 +O 2 ⟶CO 2 +2H

CH 4 +O 2 ⟶CO 2 +2H 2

CH 4 +O 2 ⟶CO 2 +2H 2

CH 4 +O 2 ⟶CO 2 +2H 2 O

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/mol

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are:

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: =

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: = 44

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: = 441

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: = 441

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: = 441 ×22=0.5 mol

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: = 441 ×22=0.5 mol

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