Question

How many moles of H2O are present in 1.8 g of water ?

Give answer with explanation​

Answer 1

Answer:

1.8g of H2O=1.818=0.1 mol H2O.

Solution

At ordinary temperature, density of water

=1g*mL^(-1)

<br>

therefore

Mass of 1.8 mL of water

=1.8xx1=1.8g

: <br> Now, 1.8g of

H_(2)O=(1.8)/(18)=0.1

mol

H_(2)O

Explanation:

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Answer 2

Answer:

Now, 1.8g of H2O=1.818=0.1 mol H2O

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