how many moles of H2O formed by the combustion of 32g of CH4?
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The reaction = CH₄ + 2O₂ → CO₂ + 2H₂O
One mole of methane gives 2 moles of water. That is, 16g of methane gives 36 g of water
one mole of water weighs 18g and one mole of methane weighs 16g
So, 2 moles of methane will weigh: 16 x 2 = 32g
The reaction will be:
2CH₄ + 4O₂ → 2CO₂ + 4H₂O
And 32g of methane will produce 4 x 18 = 72g of H₂O
4 moles of water is produced
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