How many moles of h2o is present in 180g of water molecules?
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molecular mass of H20 = 18 g
18 g of water= 1mol
1 g = 1/18 mol
180 g= 180×1/18= 10 mol
18 g of water= 1mol
1 g = 1/18 mol
180 g= 180×1/18= 10 mol
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1
Solution :
we need to find out number of moles present in 180g of water molecules.
we know that,
n = Given mass/molar mass
where,
- n = number of moles
Molar mass of water H2O :
= 1 × 2 + 16
= 18 g
number of moles :
= 180g/18g
= 10 mol
Hence
- Number of moles present in 180g of water molecules is 10mol
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