Question

How many moles of H2SO4 are required to neutralize 4 litres of 2 N NaoH solution?​

Answer 1

How many moles of h2so4 are required to neutralize 4 litre of 2n naoh solun?

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4- LITRES of 2N NaOH contains = (4 x2)= 8-moles

Here(1-N= 1-M)

We know

2 NaOH+ H2SO4 ===> Na2SO4 + 2H2O.

From the above equation we come to know that 2- moles of NaOH will neutralise 1- mole of H2SO4.

Therefore 8- moles of NaOH will neutralise 4- moles of H2SO4 or

(98 x4)= 392-g of H2SO4.

Answer 2

Give:

Volume of NaOH $=4 litres$

Normality of NaOH $=2 N$

To Find: Number of moles of $\[{H_2}S{O_4}\]$ required to neutralize 4 litres of 2 N NaOH solution

Solution:

The reaction of neutralization of NaOH by $\[{H_2}S{O_4}\]$ can be given as:

$\[{H_2}S{O_4} + 2NaOH \to N{a_2}S{O_4} + 2{H_2}O\]$

As two moles of NaOH are required to replace 2 $\[{H^ + }\]$ ions.

Therefore, the value of n-factor for this reaction is 1.

Thus,

$\[Normality = n \times Molarity\]$

$\[Normality = Molarity\]$

Therefore, the morlarity of NaOH solution is 2 M.

Thus, the number of moles of NaOH can be calculated as:

$\[Number\,of\,moles = Molarity \times Volume\]$

$\[Number\,of\,moles = 2 \times 4\]$

$\[Number\,of\,moles = 8\,mol\]$

From the above reaction, 2 moles of NaOH neutralize 1 mole of $\[{H_2}S{O_4}\]$

1 mole of NaOH neutralizes 1/2 mole of $\[{H_2}S{O_4}\]$

Therefore,

8 moles of NaOH will neutralize $\[8 \times \frac{1}{2} = 4\]$ moles of $\[{H_2}S{O_4}\]$

Hence, the number of moles of $\[{H_2}S{O_4}\]$ required to neutralize 4 litres of 2 N NaOH solution is 4 moles.