Question

How many moles of HCl are in 75.0 mL of 0.200 M solution?

Answer 1

Answer:

0.015 moles.

Explanation:

These questions can easily be resolved using the relationship that concentration (or molarity) m = no. of moles / no. of litres.

In this case, simply rearrange for no. of moles.

No. of moles = molarity x no. of litres = 0.2 x (75/1000) = 0.015 mol.

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Answer 2

We have to find the number of moles of HCl are in 75 g mL of 0.200 M solution.

What is molarity ?

it is just a way to express the concentration of a solution. it is defined as the ratio of number of moles of solute to the volume of solution in liters.

in short, molarity = no of moles of solute/volume of solution in L

⇒ no of moles of solute = molarity × volume of solution in L

here the volume of the solution = 75 mL = 75/1000 L = 0.075 L

molarity of the solution = 0.2 M

now the number of moles of HCl = molarity × volume of HCl of solution

= 0.2 × 0.075 mol

= 0.015 mol

Therefore 0.015 moles of HCl present in 75 mL of 0.200 M solution.