Question

How many moles of hcl must be removed from 1 litre of aqueous?

Answer 1

Answer:

When the pH of a solution is 12 ,it's pOH=2

The OH- ion concentration =0.01N.

So weight of NaOH present in 1 liter of 0.01 N solution = 0.01 x 40= 0.4 gm

If the pH of the solution is reduced to 11, the

OH- ion concentration will be= 0.001 N

So the weight of NaOH present in 1 liter of 0.001 N solution =0.001 x 40 = 0.04 gm.

So the weight of NaOH that is to be removed from the solution of pH=12,

is (0.4–0.04)=0.36 gm.

So No.of moles of NaOH that is to be removed is = weight/equivalent = 0.36/40=0.009 moles.

Answer 2

Answer:

When the pH of a solution is 12 ,it's pOH=2

The OH- ion concentration =0.01N.

So weight of NaOH present in 1 liter of 0.01 N solution = 0.01 x 40= 0.4 gm

If the pH of the solution is reduced to 11, the

OH- ion concentration will be= 0.001 N

So the weight of NaOH present in 1 liter of 0.001 N solution =0.001 x 40 = 0.04 gm.

So the weight of NaOH that is to be removed from the solution of pH=12,

is (0.4–0.04)=0.36 gm.

So No.of moles of NaOH that is to be removed is = weight/equivalent = 0.36/40=0.009 moles.