How many moles of helium gas occupy 2.4 litres at 0℃ at 1 atmospheric pressure
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P = 1 atm
V = 2.4 l
T = 0℃ = 273k
n = ?
Apply. PV = nRT
1 × 2.4 = n × 0.0821 × 273
2.4 / 22.4 = n
n = 0.107
Hence it contains 0.107 moles
Thanks
V = 2.4 l
T = 0℃ = 273k
n = ?
Apply. PV = nRT
1 × 2.4 = n × 0.0821 × 273
2.4 / 22.4 = n
n = 0.107
Hence it contains 0.107 moles
Thanks
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