Question

How many moles of helium gas occupy 22.4 l at o0c and 1atm pressure?

Answer 1

Hello! Let me try to answer this ^ ^

$p.V = n.R.T$
$n = \frac{p.V}{R.T}$
$n = \frac{(1 atm).(22.4 L)}{(0.082 L atm/mole K).(273 K)}$
$n = 1 mole$

NB: 0 degree Celcius = 273 K

Thanks, pease correct if there are any mistakes :)