How many moles of HNO3 will be required to decrease the molarity of 500ml solution of CA(OH)2 from 0.5M to 0.4M?
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3.15g per 500 ml = 6.30g per 1000ml = 6.30g/63.01g/mol
= 0.09998M
=0.1 Molar HNO3
IF YOU LIKED IT MARK IT AS BRAINILEST!!!!
= 0.09998M
=0.1 Molar HNO3
IF YOU LIKED IT MARK IT AS BRAINILEST!!!!
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It's ok even if the answer is not completely step-wise.
IT'S OK BUT IF YOU COULD WRITE THE STEPS IT'S EVEN BETTER
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