How many moles of hydrogen are there in 0.925 gram of ca(oh)2 where ca is equals to 40 AMU
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Answer:
(0.925 g Ca(OH)2) / (74.0927 g Ca(OH)2/mol) x (2 mol H / 1 mol Ca(OH)2) = 0.0250 mol H atoms
(If you need moles of H2 molecules, divide the answer above by 2.)
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Answer:
0.025 moles of hydrogen
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