how many moles of hydrogen gas will be evolved when 6.5gm of granulated zinc(at wt=65) is dipped in excess of hydrochloric acid zn+2hcl------->zncl2+h2
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Answered by
13
Hey,
answer is 0.1 mole of Hydrogen is liberated.
Refer to image attached
HOPE THIS HELPS YOU.
answer is 0.1 mole of Hydrogen is liberated.
Refer to image attached
HOPE THIS HELPS YOU.
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aakash69:
thank you so much
welcome.
but how 1 mole of zn leads to 1ole of h2
I've written eq. in the image attached..refer to that eq.
1 mole Zinc+ 2moles HCl will give 1 mole Zncl2 and 1 mole H2
Answered by
9
Answer:
0.05 mole of H2 will be produced .
Explanation:
Zn + 2HCl — ZnCl2 + H2
65g Zn reacts with 2x6.023x10^23 molecules of HCl
Hence , 6.50g Zn requires 2x6.023x10^22 molecules of HCl to react completely .
But we have used only 6.023x10^22 molecules of HCl. Hence , you can see that molecules of HCl are less than required for 6.5g Zn to react completely . So , the reaction will occur only until HCl is present .
So , now ,from above reaction ,
When 2*6 023*10^23 HCl is consumed , 1 mole of H2 is produced .
Hence , when 6.023*10^22 HCl is consumed , 0.05 mole of H2 will be produced .
Hope it will help
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