Question

How many moles of hydrogen required to producing 42 g ammonia, after completion of reaction?​

Answer 1

Answer:

The molar mass of ammonia is 17 g/mol.

68 grams of ammonia corresponds to

17g/mol

68g

=4moles

4 moles of ammonia will be obtained from

2

4×1

=2 moles of nitrogen and

2

4×3

=6 moles of hydrogen.

The molar masses of nitrogen and hydrogen are 28 g/mol and 2 g/mol respectively.

2 moles of nitrogen corresponds to 2×28=56 grams.

6 moles of hydrogen corresponds to 6×2=12 grams.

Explanation:

you can mark me as brainliest.

Answer 2

Answer:126/17moles

Explanation:

N2+3H2GIVES 2NH3

3 moles of  H2 reacts to give 2 moles of NH3

In terms of weight

2*17 gives 3*2 grams

42 gives 42/17*2 *6

So answer will be 126/17=7.41g

n=w/m=7.41/1

Thus answer is 7.41 moles