how many moles of kclo3 are to be heated for producing 11.2l of O2 at stp
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2KClo3 - 2KCl+3O2
2moles of kclo3- 3moles of o2
{11.2L=0.5mole}
0.5 mole of o2- 0.5×2÷3
Ans= 0.3 mole of kclo3
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11th
Chemistry
Some Basic Concepts of Chemistry
Stoichiometry and Stoichiometric Calculations
How many moles of potassium...
CHEMISTRY
How many moles of potassium chlorate to be heated to produce 11.2 L of oxygen at NTP?
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ANSWER
At NTP, 11.2 L of oxygen corresponds to
22.4
11.2
=0.5mol
2KClO
3
heat
2KCl+3O
2
Thus, 2 moles of potassium chlorate on heating gives 3 moles of oxygen.
Thus,
3
2
×0.5=
3
1
moles of potassium chlorate on heating gives 11.2 L of oxygen at NTP.
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