How many moles of KI are needed to produce 0.4moles of K2HgI4?
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The required equation is HgCl2+4KI>>2KCl+K2HgI4. according to stoichiometric calculations 4 moles of KI gives 1 mole of k2HgI4 THEREFORE 0.4moles of K2HgI4 requires----- ? 0.4 moles x 4 moles/1 mole=1.6 moles therefore1.6 moles of KI is required to produce 0.4 moles of K2HgI4.
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