Question

how many moles of KI are required to produce of 0.4moles of K2[HgI4]?

Answer 1

the required equation is HgCl2+4KI>>2KCl+K2HgI4. according to stoichiometric calculations 4 moles of KI gives 1 mole of k2HgI4 THEREFORE 0.4moles of K2HgI4 requires----- ? 0.4 moles x 4 moles/1 mole=1.6 moles therefore1.6 moles of KI is required to produce 0.4 moles of K2HgI4.

Answer 2

Answer:

To produce 0.4 moles of  $K_{2}HgCl_{2}$,  we need $1.6 moles$ of KI are required.

Explanation:

The chemical reaction:

$HgCl_{2}+4KI$   →   $2KCl+K_{2}HgCl_{4}$

From the above reaction it is observed that to produce one mole of  $K_{2}HgCl_{2}$ we need four moles of potassium iodide.

1 mole of $K_{2}HgCl_{2}$ is produced by $=4moles$ of KI

0.4 moles of $K_{2}HgCl_{2}$ required $=4*0.4=1.6 moles$ of KI

Therefore 1.6 moles of potassium iodide are required.