Chemistry, asked by Palepushivani, 1 year ago

how many moles of KI are required to produce of 0.4moles of K2[HgI4] , ehen HgCl2 reacts with KI

Answers

Answered by shivam8899
16
 HgCl2 + 2KI -----> 2KCl + HgI2 -----(1) 

 HgI2 + 2KI --------> K2[HgI4] ---------(2)

(1) + (2) 

HgCl2    +   4KI --------->  2KCl   +   K2[HgI4]-------(3)

if 0.4 mole of K2[HgI4] produce then by stoichiometry coefficient mole of KI is 4 times of mole of K2[HgI4]  from 3rd reaction

so mole of KI is 4 x 0.4 = 1.6 mole 

i hope it will help you 
regards
Similar questions