Question

how
many moles of KMnO4 required for oxidation of 1 mole of Na2SO3​

Answer 1

Answer:

Equate equivalents.

Equivalents = n−factor×moles

For KMnO

4

n-factor is 5. Let moles be 'm'.

So equivalents of KMnO

4

=5×m=5m.

n-factor for SnCl

2

is 2 as it goes from +2−+4 oxidation state. It's moles is 1.

So equivalents is 2.

5m=2

m=

5

2