How many moles of lead (¡¡) chloride will be formed from a reaction between 6.5g of pbo and 3.2g of HCl
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How many moles of pbcl2 will be formed from a reaction between 6.5g pbO and 3.2g HCl???
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byK6ashikoelpoojadpd 15.06.2016
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The equation for the reaction between PbO and HCl is as follows:
PbO + 2HCl------------> PbCl2 + Cl + H2O
Therefore 1 moles of PbO require 2 moles of HCl to give 1 mole of PbCl2.
Calculate the reagent, between HCl and PbO, that is the limiting reagent.
Pb-207.2 Cl-35.5 O-16 H-1
moles=mass/molar mass
moles of PbO = 6.5/(207+16) = 6.5/223.2 = 0.029148
if 1 mole = 2 moles of HCl
then 0.029148= 2x0.029148= 0.058296
moles of HCl= 3.2/(1+35.5) = 3.2/36.5 = 0.08767
if 2 moles of HCl= 1 mole of PbO
then 0.08767= 1x 0.8767/2 = 0.04384
Therefore PbO is the limiting reagent.
Calculate moles of PbCl2 produced as follows:
if 1 mole of PbO = 1 mole of PbCl2
then 0.029148 will give= 1 x 0.029148 moles
Therefore moles of PbCl2 produced = 0.029148 moles