Chemistry, asked by prashant849, 7 months ago

How many moles of lead (II) chloride will be formed
from a reaction between 6.5 g of PbO and 3.2 g
of HCI ? (Atomic wt. of Pb=207)
(1) 0.011
(2) 0.029
(3) 0.044
(4) 0.333​

Answers

Answered by Anonymous
4

Explanation:

PbO+2HCl→PbCl

2

+H

2

O

Atomic mass of PbO = 207 + 16 = 223

Atomic mass of HCl = 36.5

Moles of PbO =

223

6.5

= 0.029 moles

Moles of HCl =

36.5

3.2

= 0.088 moles

From the above chemical equation, we see that PbO is the limiting reagent.

∴ 1 mole of PbO gives 1 mole of PbCl

2

0.029 moles of PbO forms 0.029 moles of PbCl

2

.option b is right

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