Question

How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g of HCl?

a) 0.029
b) 0.044
c) 0.333
d) 0.011

If possible, please provide handwritten solution. ​

Answer 1

Answer:

0.029

Explanation:

PbO+2HCl→PbCl2+H2O

Atomic mass of PbO = 207 + 16 = 223

Atomic mass of HCl = 36.5

Moles of PbO = 2236.5 = 0.029 moles

Moles of HCl = 36.53.2 = 0.088 moles

From the above chemical equation, we see that PbO is the limiting reagent.

∴ 1 mole of PbO gives 1 mole of PbCl2

0.029 moles of PbO forms 0.029 moles of PbCl2.

Answer 2

Answer:

Correct option is

A 0.029

PbO + 2HCl → PbCl2 + H₂O

Atomic mass of PbO = 207 + 16 = 223 Atomic mass of HCl = 36.5

6.5 Moles of PbO = = 0.029 moles 223

Moles of HC1

3.2

36.5

=

= 0.088 moles

From the above chemical equation, we see that PbO is the limiting reagent.

.. 1 mole of PbO gives 1 mole of PbCl2

0.029 moles of PbO forms 0.029 moles of PbCl₂.

Hence, the answer is option A.

Explanation:

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