How many moles of lead nitrate is needed to produce 224 litre oxygen at NTP
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Answered by
38
Reaction for the decomposition of the lead nitrate is given below,
2Pb(NO₃)₂ ---------→ 2PbO + 4NO₂ + O₂
From this reaction,
2 mole of the Lead Nitrate is Producing 22.4 liter of Oxygen.
∴ 22.4 liter of Oxygen is Produced by the 2 mole of Lead Nitrate.
∴ 224 liter of Oxygen is Produced by the 2/22.4 × 224 = 20 mole of Lead Nitrate.
Hence, the moles of the Lead Nitrate Required to Produce 224 liter of Oxygen gas is 20.
Hope it helps.
Answered by
7
Explanation:
. ∴ 22.4 liter of Oxygen is Produced by the 2 mole of Lead Nitrate.
∴ 224 liter of Oxygen is Produced by the
2/22.4 × 224 = 20 mole
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