Chemistry, asked by aanyakkumar232, 1 year ago

how many moles of liquid water must freeze to remove 100 kJ of heat?

Answers

Answered by myrakincsem
5
Hf = - 334 J/g

As there a 1000 joules in a kilo joule.

Hf = - 334 J/g ÷ 1000 J/ kj = - 0.334 kJ/g

100 kJ ÷ - 0.334 kJ/g  = 299 g

Conversion to mole by using molecular weight of water 18.0 g/mole

299 ÷ 18.0 = 16.6 moles 

Therefore, 16.6 moles of liquid water should be frozen to remove 100 kJ of heat.

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