how many moles of liquid water must freeze to remove 100 kJ of heat?
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Hf = - 334 J/g
As there a 1000 joules in a kilo joule.
Hf = - 334 J/g ÷ 1000 J/ kj = - 0.334 kJ/g
100 kJ ÷ - 0.334 kJ/g = 299 g
Conversion to mole by using molecular weight of water 18.0 g/mole
299 ÷ 18.0 = 16.6 moles
Therefore, 16.6 moles of liquid water should be frozen to remove 100 kJ of heat.
As there a 1000 joules in a kilo joule.
Hf = - 334 J/g ÷ 1000 J/ kj = - 0.334 kJ/g
100 kJ ÷ - 0.334 kJ/g = 299 g
Conversion to mole by using molecular weight of water 18.0 g/mole
299 ÷ 18.0 = 16.6 moles
Therefore, 16.6 moles of liquid water should be frozen to remove 100 kJ of heat.
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