How many moles of magnesium phosphate will contain 0.25 moles of oxygen atoms
Answers
Answered by
177
1 mole of Mg3(PO4)2 contains 8 moles of Oxygen
Then,
8 moles of oxygen is contained by 1 mole of Mg3(PO4)2.
0.25 moles of oxygen is contained by [ (0.25*1) ÷ 8 ] = 25 ÷ 800 = 0.03125 moles of Mg3(PO4)2.
So, your answer is 0.03125 moles
Then,
8 moles of oxygen is contained by 1 mole of Mg3(PO4)2.
0.25 moles of oxygen is contained by [ (0.25*1) ÷ 8 ] = 25 ÷ 800 = 0.03125 moles of Mg3(PO4)2.
So, your answer is 0.03125 moles
Answered by
40
Explanation:
step by step explanation:
here given oxygen mole
so 8 mole of oxygen:-1 mole Mg3(po4)2
0.25 mole of oxygen:-?
0.25×1÷8
=0.03125
=3.125×10^-2
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