Question

how many moles of Methane are required to produce 22 gram of Co2 gram after cobustion?​

Answer 1

$\bold{\Huge\red{\boxed{{{Answer}}}}}$

CH

CH 4

CH 4

CH 4 +O

CH 4 +O 2

CH 4 +O 2

CH 4 +O 2 ⟶CO

CH 4 +O 2 ⟶CO 2

CH 4 +O 2 ⟶CO 2

CH 4 +O 2 ⟶CO 2 +2H

CH 4 +O 2 ⟶CO 2 +2H 2

CH 4 +O 2 ⟶CO 2 +2H 2

CH 4 +O 2 ⟶CO 2 +2H 2 O

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/mol

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are:

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: =

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: = 44

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: = 441

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: = 441

CH 4 +O 2 ⟶CO 2 +2H 2 OGram molecular mass of CO2 = 12 +2(16) = 44g/molFrom the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.Therefore moles of CH 4 required to produce 22g of CO 2 are: = 441 ×22=0.5 mol

$\red {\boxed{\boxed{\boxed{5 \: Thanks +Follow =Inbox}}}}</em></p><p></p><p><em>[tex]\red {\boxed{\boxed{\boxed{5 \: Thanks +Follow =Inbox}}}}$