Question

how many moles of Methane are required to produce 22 gram of co2for combustion

Answer 1

By unitary method and stoichiometric calculation,

CH4 + 2O2 → CO2 + 2H2O

1 mol of methane → 1 mol of carbon dioxide (→ indicates “gives”)

Hence 16 g of methane → 44g of carbon dioxide

So, x (say) grams of methane → 22g of carbon dioxide

By unitary method,

x=16/44 * 22 = 8 g of methane

Converting 8 grams of methane to moles:

8/16=0.5 moles

hence your answer is 1/2moles

Answer 2

HEYA MATE HERE U GO.

❤. According to the chemical equation

CH4 (g) + 202(g)------> CO2 (g) + 2H2O(g).

44gm of CO2 is obtained -1 mole of CH4 is

22gm of CO2 is obtained -?

required = 22×1 /44 = 0.5

0.5 moles of CH4 is required.