how many moles of Methane are required to produce 22 grams of carbon dioxide gas after combustion
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By unitary method and stoichiometric calculation,
CH4 + 2O2 → CO2 + 2H2O
1 mol of methane → 1 mol of carbon dioxide (→ indicates “gives”)
Hence 16 g of methane → 44g of carbon dioxide
So, x (say) grams of methane → 22g of carbon dioxide
By unitary method,
x=16/44 * 22 = 8 g of methane
Converting 8 grams of methane to moles:
8/16=0.5 moles
hence your answer is 1/2moles
Hope this helped!!!
sciencegeekmeyo:
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