How many moles of methane are required to produce 88g of co2 after combustion?
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Answered by
79
CH4 + 2O2 -> CO2 + 2H2O
GRAM MOLECULAR MASS OF CO2 = 12 +2(16) = 44g
From the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.
therefore moles of CH4 required to produce 88g of CO2 are:
(88) * (1/44) = 2 moles
GRAM MOLECULAR MASS OF CO2 = 12 +2(16) = 44g
From the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.
therefore moles of CH4 required to produce 88g of CO2 are:
(88) * (1/44) = 2 moles
Answered by
7
Chemical Equation:
CH₄+ 2 O₂ -------------------> CO₂ + 2H₂O
now,
molecular mass of CO₂ = 12 + 2 * 16 = 44 gm
By Chemical equation,
1 mole of CH₄ on complete combustion produces 1mole (44gm) of CO₂.
∴ moles of CH₄ required to produce 88gm CO₂ = 88 / 44 = 2 moles.
So, moles of methane is required to produce 88g of CO₂ after combustion = 2 moles.
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