Question

how many moles of methane are required to produced 22g of carbon dioxidegas after combustion​

Answer 1

Answer:

1/2 moles

Explanation:

Ch4 + 4o2 = co2 + 2h20

Moles of co2= 22÷44=1/2

Hence moles of ch4 is 1/2

Answer 2

Answer:

Well, where is your stoichiometric equation…? We follow the rigmarole, (i) balance the carbons as carbon dioxide, (ii) then balance the hydrogens as water, and (iii) then balance the oxygens as dioxygen gas…

And so for methane…

CH4(g)+2O2(g)→CO2(g)+2H2O(l)CH4(g)+2O2(g)→CO2(g)+2H2O(l)

And with respect to water, we produce a molar quantity of …

22.0∙g18.01∙g∙mol−1=1.22∙mol22.0•g18.01•g•mol−1=1.22•mol.

And thus there were 1.22∙mol21.22•mol2 with respect to methane, i.e. a mass of approx. 10∙g10•g.