Question

How many moles of methane are required to product 22 grams carbon dioxide after combustion?

Answer 1

CH4 + 2O2 = CO2 + H2O
No of mole = 22 / ( 12 + 2( 16 ))
= 0.5 mol

Answer 2

Answer : 0.5  moles of methane are required to product 22 grams carbon dioxide after combustion.

Solution : Given,

Mass of carbon dioxide = 22 g

Molar mass of carbon dioxide = 44 g/mole

First we have to calculate the moles of carbon dioxide.

Moles of $CO_2$ = $\frac{\text{ Given mass of }CO_2}{\text{ Molar mass of }CO_2}=\frac{22g}{44g/mole}=0.5moles$

The balanced combustion reaction is,

$CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(l)$

From the given reaction, we conclude that

As, 1 mole of $CO_2$ produces from 1 mole of $CH_4$

0.5 moles of $CO_2$ produces from 0.5 mole of $CH_4$

Therefore, the moles of methane required are 0.5 moles.