Question

How many moles of mg3(po4)2 will contain 0.25 moles of oxygen atoms?

Answer 1

Answer:

Explanation:

1 mole of magnesium phosphate compound(Mg3(PO4)2) will contain 8 moles oxygen atom. So,moles of magnesium phosphate that contains 0.25 mole of oxygen atom= 0.25/8=0.03125 mol=3.1*10^-2 mol.

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