Question

How many moles of Mg3(PO4)2 will contain
0.32 mole of oxygen atoms?​

Answer 1

Hey Dear,

◆ Answer -

Moles of Mg3(PO4)2 = 0.04 moles

● Explanation -

Compound Mg3(PO4)2 contains 8 atoms of oxygen. Thus each mole of Mg3(PO4)2 contains 8 moles of oxygen atoms.

No of moles of Mg3(PO4)2 that contain 0.32 moles of oxygen are -

Moles of Mg3(PO4)2 = moles of oxygen / 8

Moles of Mg3(PO4)2 = 0.32 / 8

Moles of Mg3(PO4)2 = 0.04 moles

Therefore, 0.04 moles of Mg3(PO4)2 will contain 0.32 mole of oxygen atoms.

Thanks dear....