How many moles of Mg3(PO4) will contain 0.25 mole of O atom Mole concept
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1 mole of magnesium phosphate compound(Mg3(PO4)2) will contain 8 moles oxygen atom. So,moles of magnesium phosphate that contains 0.25 mole of oxygen atom= 0.25/8=0.03125 mol=3.1*10^-2 mol. This is AIEEE question asked in 2010 or 11. And, 0.25 mole O atom will have 0.25*1/8 =1/32 moles.
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