Chemistry, asked by Snehadeep7041, 9 months ago

How many moles of n2 is needed to produce 8.2 moles of nh3?

Answers

Answered by spandy102
2

Answer:

4.1 mol

Explanation:

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Secondary SchoolChemistry 13 points

HOW MANY MOLES OF NITROGEN ARE NEEDED TO PRODUCE 8.2 MOLE OF AMMONIA BY THE REACTION WITH HYDROGEN?

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jacekylie1 Ambitious

Here is how you crack it up;

write a balanced chemical equation for the reaction

N + H ⇄ NH3

since these elements exist as diatomic gases,

∴N2 + H2 ⇄ NH3

now to balance it, make sure the number of atoms on both sides of the equation are equal, thus;

N2 + 3H2 ⇄ 2NH3. Now to compare the mole ratios

there is 1mol of N2 which reacted with 3mol of H2 to produce 2mol of NH3

we say, 1mol(N2) : 2mol(NH3)

Xmol : 8.2mol , and to do the calculation,

2X = 8.2,

= 4.1mol of N2

Hence, 4.1mol of N2 were needed to produce 8.2moles of NH3

Answered by veerankikarthikeya
3

Answer:so the equation is xn2+yh2=8.2nh3

Explanation:

but we know that every 1 N atom bonds with 3h atoms

so, the equation is (8.2/2)n2+(8.2/2)h2=8nh3  or

4.1n2+12.3h2=8.2nh3

change in free energy:^g(20c)=-138.6kj

change in enthalpy::-375.8kj

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