How many moles of n2 is needed to produce 8.2 moles of nh3?
Answers
Answer:
4.1 mol
Explanation:
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Secondary SchoolChemistry 13 points
HOW MANY MOLES OF NITROGEN ARE NEEDED TO PRODUCE 8.2 MOLE OF AMMONIA BY THE REACTION WITH HYDROGEN?
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jacekylie1 Ambitious
Here is how you crack it up;
write a balanced chemical equation for the reaction
N + H ⇄ NH3
since these elements exist as diatomic gases,
∴N2 + H2 ⇄ NH3
now to balance it, make sure the number of atoms on both sides of the equation are equal, thus;
N2 + 3H2 ⇄ 2NH3. Now to compare the mole ratios
there is 1mol of N2 which reacted with 3mol of H2 to produce 2mol of NH3
we say, 1mol(N2) : 2mol(NH3)
Xmol : 8.2mol , and to do the calculation,
2X = 8.2,
= 4.1mol of N2
Hence, 4.1mol of N2 were needed to produce 8.2moles of NH3
Answer:so the equation is xn2+yh2=8.2nh3
Explanation:
but we know that every 1 N atom bonds with 3h atoms
so, the equation is (8.2/2)n2+(8.2/2)h2=8nh3 or
4.1n2+12.3h2=8.2nh3
change in free energy:^g(20c)=-138.6kj
change in enthalpy::-375.8kj