How many moles of Na+ ions are present in 275.0 mL of 0.35 M Na3PO4 solution?
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Answered by
0
Answer:
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Answered by
0
Answer:
1 molecule of Na
3
PO
4
dissociates to give 3 sodium ions.
The number of moles of Na
+
ions present in 20 mL of 0.40 M Na
3
PO
4
=
1000
20
×0.40×3=0.024.
Thus, 0.024 mol of Na
+
ions are present in 20 mL of 0.40 M Na
3
PO4
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