Chemistry, asked by shefalirai1065, 8 months ago

how many moles of Na2CO3 are present in 212 gram of it

Answers

Answered by legendarybrofist

5

4 moles approx

Explanation:

Na=11u*2=22u

C=6u

O=8u*3=24u

Total atomic mass=52u

Therefore 52u=1mole

Therefore 212gm =212/52=4.07moles

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