how many moles of na2s203 are needed
to react completely with 42.7g of AgBr
according to the following reaction
Na2S203+AgBr-NaBr+Na[Ag(S203)2]
Answers
Answered by
1
Explanation:
That is 2 moles By balancing equation
Answered by
0
Answer:
here's your answer.....
2 mole
Similar questions