Question

How many moles of Nacl are contained in 100.0 of a 0.200m solution​

Answer 1

Answer:

0.200 M = x / 0.1000 L

x =  0.0200 mol

Answer 2

(There is some mistake in the question. It should be 100.0 mL of a 0.200 M solution.)

Given:

Volume of NaCl solution $\[ = 100.0\,mL\]$

Molarity of NaCl solution $\[ = 0.200\,M\]$

To Find: Number of moles of NaCl solution

Solution:

Molarity of a solution is given as:

$\[M = \frac{n}{V} \times 1000\]$

where, $n=$ no. of moles, $V=$ volume of solution

Therefore, the number of moles can be given as:

$\[n = \frac{{{\rm M} \times V}}{{1000}}\]$

$\[n = \frac{{0.200 \times 100.0}}{{1000}}\]$

$\[n = 0.02\]$

Hence, the number of moles of NaCl contained in 100.0 mL of a 0.200 M solution is 0.02.