Question

How many moles of NaCl are produced from 15.5g of HCl according to neutralization reaction?

Answer 1

Answer:

HCl + NaOH → NaCl + H2O

mole of HCl=$\frac{15.5}{36.5}$

moles of NaCl = moles of HCl

then moles of NaCl = $\frac{15.5}{36.5}$ = 0.424

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Answer 2

Given:

The mass of HCl = 15.5 gm

To Find:

The no of moles of NaCl formed on neutralization reaction.

Calculation:

- The neutralization reaction of HCl is given as:

HCl + NaOH → NaCl + H2O

- The mass of NaCl formed by 36.5 gm of HCl = 58.5

⇒ The mass of NaCl formed by 15.5 gm of HCl = (58.5 / 36.5) × 15.5 = 24.8 gm

- The no of moles of NaCl = 24.8 / 58.5 = 0.424 moles

- So, the no of moles of NaCl formed on neutralization reaction of 15.5 gm of HCl is 0.424 moles.