Question

How many moles of NaCl is present in 500 mL of centimolar NaCl (aq) solution?
​

Answer 1

Explanation:

Molarity= moles of solute/Liters of solution

1.55 M

=

moles

.5

moles = 0.775 moles of NaCl

Explanation:

Molarity

=

moles of solute

Liters of solution

First, we need to convert

500 mL

to Liters

500 ml

⋅

1 L

1000 ml

=

.5 L

Now we can plug into our formula

1.55M

=

moles

.5

moles = 0.775 moles of NaCl

Hope it was helpful!

please mark me as branlist