How many moles of naoh are needed to dissolve in water to make 3 litres of 2.0 m solution?
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Answer:
Explanation:
he case of NaOH normality and molarity is the same.
10% NaOH solution
Normality first calc equivalnt weight (ew)
ew - molecular mass expressed in grams/ basicity
NaOH ==
ew — 23 + 16+ 1 = 40/1= 40g
dissolve this in 1000 mls same as litre or 1000cc distilled water to get a 1N solution.
N/10 is a 0.1 N solution therefore 40g * 0.1 - 4g
N/10 solution - 4g NaOH dissolved in I litre water
confirm by titration using Oxalic acid and Phenolpthalein indicator light pink colour
use equation N1V1/N2V2 equal A/B
Ph is the negative log or antilog of the hydroxyl ion concentration
concentration of OH ion is the same as the basicity which is one
antilog of one to base 10 give
Ph of 13.
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