Question

How many moles of NaOH are present in 3L of water, if pH of solution is 10 ?

Answer 1

Answer:

2L of water

Explanation:

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Answer 2

Given:

The volume of NaOH solution, V = 3 L

The pH of NaOH solution = 10

To Find:

The number of moles of NaOH present in the 3 L of solution.

Calculation:

- We know the relationship as:

pH + pOH = 14

⇒ 10 + pOH = 14

⇒ pOH = 4

- Now, the concentration of OH⁻ can be calculated by the formula:

pOH = -log[OH⁻]

⇒ 4 = -log[OH⁻]

⇒ [OH⁻] = 10⁻⁴ M

- So, the concentration of NaOH is 10⁻⁴ M.

- The number of moles of NaOH = V × M

⇒ n = 3 × 10⁻⁴

- So, the number of moles of NaOH present in 3 L of water is 3 × 10⁻⁴.