Question

How many moles of neutron are present in one mole of heavy water

Answer 1

I’ll assume the heavy water has only deuterium and no normal hydrogen-1 atoms. Assume all the oxygen in the water is normal oxygen-16.

So, one molecule of heavy water will have 10 neutrons (one in each of the two deuterium atoms and 8 in the oxygen atom.

A mole of anything contains 6.02E23 items.

So a mole of heavy water will have 60.02E23 (6.02E24) neutrons.

Answer 2

Concept :

In contrast to normal water, which mostly contains the common hydrogen-$1$ isotope, heavy water is a kind of water that only contains deuterium. Heavy water, created by replacing the hydrogen atoms in conventional water with their denser relative deuterium, resembles regular water in appearance and flavor and is safe to consume in small amounts (no well over five tablespoons for an adult). A different approach uses electrolysis to create hydrogen and oxygen from water, which also produces deuterium. Deuterium is then combined with oxygen to create heavy water after the hydrogen has been liquefied and purified to split the two parts.

Given: heavy water

Find, how many moles of the neutron are present in one mole of heavy water

Solution:

I’ll assume the heavy water has only deuterium and no normal hydrogen-$1$ atoms. Assume all the oxygen in the water is normal oxygen-$16$.

So, one molecule of heavy water will have $10$ neutrons (one in each of the two deuterium atoms and $8$ in the oxygen atom.

A mole of anything contains $6.022$ × $10^2^3$ items.

So a mole of heavy water will have $6.022$ × $10^2^4$ neutrons.

Hence a mole of heavy water will have $6.022$ × $10^2^4$ neutrons.

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