How many moles of NH3 are there in 77.5 g of NH3?
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Answered by
5
4.56 moles because
77.5 given mass
17 molar mass
moles will be 77.5/17
i.e. 4.56 moles
Answered by
0
So, 5 moles of NH3 will contain 3 × 5 × 6.023 × 10²³ H atoms. 1 mole ammonia having 6.022*10^23 molecule. Three H atoms per molecule, so it would be 3 moles of H per mole of ammonia and then multiply it by 5.
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